3[5c-1]=4[3c+2]

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Solution for 3[5c-1]=4[3c+2] equation:


Simplifying
3[5c + -1] = 4[3c + 2]

Reorder the terms:
3[-1 + 5c] = 4[3c + 2]
[-1 * 3 + 5c * 3] = 4[3c + 2]
[-3 + 15c] = 4[3c + 2]

Reorder the terms:
-3 + 15c = 4[2 + 3c]
-3 + 15c = [2 * 4 + 3c * 4]
-3 + 15c = [8 + 12c]

Solving
-3 + 15c = 8 + 12c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12c' to each side of the equation.
-3 + 15c + -12c = 8 + 12c + -12c

Combine like terms: 15c + -12c = 3c
-3 + 3c = 8 + 12c + -12c

Combine like terms: 12c + -12c = 0
-3 + 3c = 8 + 0
-3 + 3c = 8

Add '3' to each side of the equation.
-3 + 3 + 3c = 8 + 3

Combine like terms: -3 + 3 = 0
0 + 3c = 8 + 3
3c = 8 + 3

Combine like terms: 8 + 3 = 11
3c = 11

Divide each side by '3'.
c = 3.666666667

Simplifying
c = 3.666666667

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